6x(x-8)=2x^2-49x

Solution for 6x(x-8)=2x^2-49x equation:

6x(x-8)=2x^2-49x

We move all terms to the left:

6x(x-8)-(2x^2-49x)=0

We multiply parentheses

6x^2-48x-(2x^2-49x)=0

We get rid of parentheses

6x^2-2x^2-48x+49x=0

We add all the numbers together, and all the variables

4x^2+x=0

a = 4; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·4·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*4}=\frac{-2}{8}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*4}=\frac{0}{8}
=0
$